3.1.49 \(\int (a+b \cos (c+d x))^3 (e \sin (c+d x))^{7/2} \, dx\) [49]

Optimal. Leaf size=242 \[ \frac {10 a \left (11 a^2+6 b^2\right ) e^4 F\left (\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {\sin (c+d x)}}{231 d \sqrt {e \sin (c+d x)}}-\frac {10 a \left (11 a^2+6 b^2\right ) e^3 \cos (c+d x) \sqrt {e \sin (c+d x)}}{231 d}-\frac {2 a \left (11 a^2+6 b^2\right ) e \cos (c+d x) (e \sin (c+d x))^{5/2}}{77 d}+\frac {2 b \left (177 a^2+44 b^2\right ) (e \sin (c+d x))^{9/2}}{1287 d e}+\frac {34 a b (a+b \cos (c+d x)) (e \sin (c+d x))^{9/2}}{143 d e}+\frac {2 b (a+b \cos (c+d x))^2 (e \sin (c+d x))^{9/2}}{13 d e} \]

[Out]

-2/77*a*(11*a^2+6*b^2)*e*cos(d*x+c)*(e*sin(d*x+c))^(5/2)/d+2/1287*b*(177*a^2+44*b^2)*(e*sin(d*x+c))^(9/2)/d/e+
34/143*a*b*(a+b*cos(d*x+c))*(e*sin(d*x+c))^(9/2)/d/e+2/13*b*(a+b*cos(d*x+c))^2*(e*sin(d*x+c))^(9/2)/d/e-10/231
*a*(11*a^2+6*b^2)*e^4*(sin(1/2*c+1/4*Pi+1/2*d*x)^2)^(1/2)/sin(1/2*c+1/4*Pi+1/2*d*x)*EllipticF(cos(1/2*c+1/4*Pi
+1/2*d*x),2^(1/2))*sin(d*x+c)^(1/2)/d/(e*sin(d*x+c))^(1/2)-10/231*a*(11*a^2+6*b^2)*e^3*cos(d*x+c)*(e*sin(d*x+c
))^(1/2)/d

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Rubi [A]
time = 0.21, antiderivative size = 242, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.240, Rules used = {2771, 2941, 2748, 2715, 2721, 2720} \begin {gather*} \frac {10 a e^4 \left (11 a^2+6 b^2\right ) \sqrt {\sin (c+d x)} F\left (\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right )}{231 d \sqrt {e \sin (c+d x)}}-\frac {10 a e^3 \left (11 a^2+6 b^2\right ) \cos (c+d x) \sqrt {e \sin (c+d x)}}{231 d}+\frac {2 b \left (177 a^2+44 b^2\right ) (e \sin (c+d x))^{9/2}}{1287 d e}-\frac {2 a e \left (11 a^2+6 b^2\right ) \cos (c+d x) (e \sin (c+d x))^{5/2}}{77 d}+\frac {2 b (e \sin (c+d x))^{9/2} (a+b \cos (c+d x))^2}{13 d e}+\frac {34 a b (e \sin (c+d x))^{9/2} (a+b \cos (c+d x))}{143 d e} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*Cos[c + d*x])^3*(e*Sin[c + d*x])^(7/2),x]

[Out]

(10*a*(11*a^2 + 6*b^2)*e^4*EllipticF[(c - Pi/2 + d*x)/2, 2]*Sqrt[Sin[c + d*x]])/(231*d*Sqrt[e*Sin[c + d*x]]) -
(10*a*(11*a^2 + 6*b^2)*e^3*Cos[c + d*x]*Sqrt[e*Sin[c + d*x]])/(231*d) - (2*a*(11*a^2 + 6*b^2)*e*Cos[c + d*x]*
(e*Sin[c + d*x])^(5/2))/(77*d) + (2*b*(177*a^2 + 44*b^2)*(e*Sin[c + d*x])^(9/2))/(1287*d*e) + (34*a*b*(a + b*C
os[c + d*x])*(e*Sin[c + d*x])^(9/2))/(143*d*e) + (2*b*(a + b*Cos[c + d*x])^2*(e*Sin[c + d*x])^(9/2))/(13*d*e)

Rule 2715

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(-b)*Cos[c + d*x]*((b*Sin[c + d*x])^(n - 1)/(d*n))
, x] + Dist[b^2*((n - 1)/n), Int[(b*Sin[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1] && Integ
erQ[2*n]

Rule 2720

Int[1/Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticF[(1/2)*(c - Pi/2 + d*x), 2], x] /; FreeQ
[{c, d}, x]

Rule 2721

Int[((b_)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Dist[(b*Sin[c + d*x])^n/Sin[c + d*x]^n, Int[Sin[c + d*x]
^n, x], x] /; FreeQ[{b, c, d}, x] && LtQ[-1, n, 1] && IntegerQ[2*n]

Rule 2748

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(-b)*((g*Co
s[e + f*x])^(p + 1)/(f*g*(p + 1))), x] + Dist[a, Int[(g*Cos[e + f*x])^p, x], x] /; FreeQ[{a, b, e, f, g, p}, x
] && (IntegerQ[2*p] || NeQ[a^2 - b^2, 0])

Rule 2771

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> Simp[(-b)*(
g*Cos[e + f*x])^(p + 1)*((a + b*Sin[e + f*x])^(m - 1)/(f*g*(m + p))), x] + Dist[1/(m + p), Int[(g*Cos[e + f*x]
)^p*(a + b*Sin[e + f*x])^(m - 2)*(b^2*(m - 1) + a^2*(m + p) + a*b*(2*m + p - 1)*Sin[e + f*x]), x], x] /; FreeQ
[{a, b, e, f, g, p}, x] && NeQ[a^2 - b^2, 0] && GtQ[m, 1] && NeQ[m + p, 0] && (IntegersQ[2*m, 2*p] || IntegerQ
[m])

Rule 2941

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*sin[(e_.)
+ (f_.)*(x_)]), x_Symbol] :> Simp[(-d)*(g*Cos[e + f*x])^(p + 1)*((a + b*Sin[e + f*x])^m/(f*g*(m + p + 1))), x
] + Dist[1/(m + p + 1), Int[(g*Cos[e + f*x])^p*(a + b*Sin[e + f*x])^(m - 1)*Simp[a*c*(m + p + 1) + b*d*m + (a*
d*m + b*c*(m + p + 1))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] && NeQ[a^2 - b^2, 0] &&
GtQ[m, 0] &&  !LtQ[p, -1] && IntegerQ[2*m] &&  !(EqQ[m, 1] && NeQ[c^2 - d^2, 0] && SimplerQ[c + d*x, a + b*x])

Rubi steps

\begin {align*} \int (a+b \cos (c+d x))^3 (e \sin (c+d x))^{7/2} \, dx &=\frac {2 b (a+b \cos (c+d x))^2 (e \sin (c+d x))^{9/2}}{13 d e}+\frac {2}{13} \int (a+b \cos (c+d x)) \left (\frac {13 a^2}{2}+2 b^2+\frac {17}{2} a b \cos (c+d x)\right ) (e \sin (c+d x))^{7/2} \, dx\\ &=\frac {34 a b (a+b \cos (c+d x)) (e \sin (c+d x))^{9/2}}{143 d e}+\frac {2 b (a+b \cos (c+d x))^2 (e \sin (c+d x))^{9/2}}{13 d e}+\frac {4}{143} \int \left (\frac {13}{4} a \left (11 a^2+6 b^2\right )+\frac {1}{4} b \left (177 a^2+44 b^2\right ) \cos (c+d x)\right ) (e \sin (c+d x))^{7/2} \, dx\\ &=\frac {2 b \left (177 a^2+44 b^2\right ) (e \sin (c+d x))^{9/2}}{1287 d e}+\frac {34 a b (a+b \cos (c+d x)) (e \sin (c+d x))^{9/2}}{143 d e}+\frac {2 b (a+b \cos (c+d x))^2 (e \sin (c+d x))^{9/2}}{13 d e}+\frac {1}{11} \left (a \left (11 a^2+6 b^2\right )\right ) \int (e \sin (c+d x))^{7/2} \, dx\\ &=-\frac {2 a \left (11 a^2+6 b^2\right ) e \cos (c+d x) (e \sin (c+d x))^{5/2}}{77 d}+\frac {2 b \left (177 a^2+44 b^2\right ) (e \sin (c+d x))^{9/2}}{1287 d e}+\frac {34 a b (a+b \cos (c+d x)) (e \sin (c+d x))^{9/2}}{143 d e}+\frac {2 b (a+b \cos (c+d x))^2 (e \sin (c+d x))^{9/2}}{13 d e}+\frac {1}{77} \left (5 a \left (11 a^2+6 b^2\right ) e^2\right ) \int (e \sin (c+d x))^{3/2} \, dx\\ &=-\frac {10 a \left (11 a^2+6 b^2\right ) e^3 \cos (c+d x) \sqrt {e \sin (c+d x)}}{231 d}-\frac {2 a \left (11 a^2+6 b^2\right ) e \cos (c+d x) (e \sin (c+d x))^{5/2}}{77 d}+\frac {2 b \left (177 a^2+44 b^2\right ) (e \sin (c+d x))^{9/2}}{1287 d e}+\frac {34 a b (a+b \cos (c+d x)) (e \sin (c+d x))^{9/2}}{143 d e}+\frac {2 b (a+b \cos (c+d x))^2 (e \sin (c+d x))^{9/2}}{13 d e}+\frac {1}{231} \left (5 a \left (11 a^2+6 b^2\right ) e^4\right ) \int \frac {1}{\sqrt {e \sin (c+d x)}} \, dx\\ &=-\frac {10 a \left (11 a^2+6 b^2\right ) e^3 \cos (c+d x) \sqrt {e \sin (c+d x)}}{231 d}-\frac {2 a \left (11 a^2+6 b^2\right ) e \cos (c+d x) (e \sin (c+d x))^{5/2}}{77 d}+\frac {2 b \left (177 a^2+44 b^2\right ) (e \sin (c+d x))^{9/2}}{1287 d e}+\frac {34 a b (a+b \cos (c+d x)) (e \sin (c+d x))^{9/2}}{143 d e}+\frac {2 b (a+b \cos (c+d x))^2 (e \sin (c+d x))^{9/2}}{13 d e}+\frac {\left (5 a \left (11 a^2+6 b^2\right ) e^4 \sqrt {\sin (c+d x)}\right ) \int \frac {1}{\sqrt {\sin (c+d x)}} \, dx}{231 \sqrt {e \sin (c+d x)}}\\ &=\frac {10 a \left (11 a^2+6 b^2\right ) e^4 F\left (\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {\sin (c+d x)}}{231 d \sqrt {e \sin (c+d x)}}-\frac {10 a \left (11 a^2+6 b^2\right ) e^3 \cos (c+d x) \sqrt {e \sin (c+d x)}}{231 d}-\frac {2 a \left (11 a^2+6 b^2\right ) e \cos (c+d x) (e \sin (c+d x))^{5/2}}{77 d}+\frac {2 b \left (177 a^2+44 b^2\right ) (e \sin (c+d x))^{9/2}}{1287 d e}+\frac {34 a b (a+b \cos (c+d x)) (e \sin (c+d x))^{9/2}}{143 d e}+\frac {2 b (a+b \cos (c+d x))^2 (e \sin (c+d x))^{9/2}}{13 d e}\\ \end {align*}

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Mathematica [A]
time = 2.58, size = 205, normalized size = 0.85 \begin {gather*} \frac {\left (154 b \left (78 a^2+11 b^2\right ) \csc ^3(c+d x)+\frac {1}{3} \left (-156 a \left (506 a^2+213 b^2\right ) \cos (c+d x)-77 b \left (624 a^2+73 b^2\right ) \cos (2 (c+d x))+234 a \left (44 a^2-39 b^2\right ) \cos (3 (c+d x))-154 b \left (-78 a^2+b^2\right ) \cos (4 (c+d x))+4914 a b^2 \cos (5 (c+d x))+693 b^3 \cos (6 (c+d x))\right ) \csc ^3(c+d x)-\frac {2080 a \left (11 a^2+6 b^2\right ) F\left (\left .\frac {1}{4} (-2 c+\pi -2 d x)\right |2\right )}{\sin ^{\frac {7}{2}}(c+d x)}\right ) (e \sin (c+d x))^{7/2}}{48048 d} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + b*Cos[c + d*x])^3*(e*Sin[c + d*x])^(7/2),x]

[Out]

((154*b*(78*a^2 + 11*b^2)*Csc[c + d*x]^3 + ((-156*a*(506*a^2 + 213*b^2)*Cos[c + d*x] - 77*b*(624*a^2 + 73*b^2)
*Cos[2*(c + d*x)] + 234*a*(44*a^2 - 39*b^2)*Cos[3*(c + d*x)] - 154*b*(-78*a^2 + b^2)*Cos[4*(c + d*x)] + 4914*a
*b^2*Cos[5*(c + d*x)] + 693*b^3*Cos[6*(c + d*x)])*Csc[c + d*x]^3)/3 - (2080*a*(11*a^2 + 6*b^2)*EllipticF[(-2*c
+ Pi - 2*d*x)/4, 2])/Sin[c + d*x]^(7/2))*(e*Sin[c + d*x])^(7/2))/(48048*d)

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Maple [A]
time = 0.18, size = 276, normalized size = 1.14

method	result	size
default	\(\frac {\frac {2 b \left (e \sin \left (d x +c \right )\right )^{\frac {9}{2}} \left (9 \left (\cos ^{2}\left (d x +c \right )\right ) b^{2}+39 a^{2}+4 b^{2}\right )}{117 e}-\frac {e^{4} a \left (-126 b^{2} \left (\cos ^{6}\left (d x +c \right )\right ) \sin \left (d x +c \right )-66 a^{2} \left (\cos ^{4}\left (d x +c \right )\right ) \sin \left (d x +c \right )+216 b^{2} \left (\cos ^{4}\left (d x +c \right )\right ) \sin \left (d x +c \right )+55 \sqrt {-\sin \left (d x +c \right )+1}\, \sqrt {2 \sin \left (d x +c \right )+2}\, \left (\sqrt {\sin }\left (d x +c \right )\right ) \EllipticF \left (\sqrt {-\sin \left (d x +c \right )+1}, \frac {\sqrt {2}}{2}\right ) a^{2}+30 \sqrt {-\sin \left (d x +c \right )+1}\, \sqrt {2 \sin \left (d x +c \right )+2}\, \left (\sqrt {\sin }\left (d x +c \right )\right ) \EllipticF \left (\sqrt {-\sin \left (d x +c \right )+1}, \frac {\sqrt {2}}{2}\right ) b^{2}+176 a^{2} \left (\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )-30 b^{2} \left (\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )\right )}{231 \cos \left (d x +c \right ) \sqrt {e \sin \left (d x +c \right )}}}{d}\)	\(276\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b*cos(d*x+c))^3*(e*sin(d*x+c))^(7/2),x,method=_RETURNVERBOSE)

[Out]

(2/117/e*b*(e*sin(d*x+c))^(9/2)*(9*cos(d*x+c)^2*b^2+39*a^2+4*b^2)-1/231*e^4*a*(-126*b^2*cos(d*x+c)^6*sin(d*x+c
)-66*a^2*cos(d*x+c)^4*sin(d*x+c)+216*b^2*cos(d*x+c)^4*sin(d*x+c)+55*(-sin(d*x+c)+1)^(1/2)*(2*sin(d*x+c)+2)^(1/
2)*sin(d*x+c)^(1/2)*EllipticF((-sin(d*x+c)+1)^(1/2),1/2*2^(1/2))*a^2+30*(-sin(d*x+c)+1)^(1/2)*(2*sin(d*x+c)+2)
^(1/2)*sin(d*x+c)^(1/2)*EllipticF((-sin(d*x+c)+1)^(1/2),1/2*2^(1/2))*b^2+176*a^2*cos(d*x+c)^2*sin(d*x+c)-30*b^
2*cos(d*x+c)^2*sin(d*x+c))/cos(d*x+c)/(e*sin(d*x+c))^(1/2))/d

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*cos(d*x+c))^3*(e*sin(d*x+c))^(7/2),x, algorithm="maxima")

[Out]

e^(7/2)*integrate((b*cos(d*x + c) + a)^3*sin(d*x + c)^(7/2), x)

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Fricas [C] Result contains higher order function than in optimal. Order 9 vs. order 4.
time = 0.16, size = 238, normalized size = 0.98 \begin {gather*} \frac {195 \, \sqrt {2} \sqrt {-i} {\left (11 \, a^{3} + 6 \, a b^{2}\right )} e^{\frac {7}{2}} {\rm weierstrassPInverse}\left (4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right ) + 195 \, \sqrt {2} \sqrt {i} {\left (11 \, a^{3} + 6 \, a b^{2}\right )} e^{\frac {7}{2}} {\rm weierstrassPInverse}\left (4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right ) + 2 \, {\left (693 \, b^{3} \cos \left (d x + c\right )^{6} e^{\frac {7}{2}} + 2457 \, a b^{2} \cos \left (d x + c\right )^{5} e^{\frac {7}{2}} + 77 \, {\left (39 \, a^{2} b - 14 \, b^{3}\right )} \cos \left (d x + c\right )^{4} e^{\frac {7}{2}} + 117 \, {\left (11 \, a^{3} - 36 \, a b^{2}\right )} \cos \left (d x + c\right )^{3} e^{\frac {7}{2}} - 77 \, {\left (78 \, a^{2} b - b^{3}\right )} \cos \left (d x + c\right )^{2} e^{\frac {7}{2}} - 39 \, {\left (88 \, a^{3} - 15 \, a b^{2}\right )} \cos \left (d x + c\right ) e^{\frac {7}{2}} + 77 \, {\left (39 \, a^{2} b + 4 \, b^{3}\right )} e^{\frac {7}{2}}\right )} \sqrt {\sin \left (d x + c\right )}}{9009 \, d} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*cos(d*x+c))^3*(e*sin(d*x+c))^(7/2),x, algorithm="fricas")

[Out]

1/9009*(195*sqrt(2)*sqrt(-I)*(11*a^3 + 6*a*b^2)*e^(7/2)*weierstrassPInverse(4, 0, cos(d*x + c) + I*sin(d*x + c
)) + 195*sqrt(2)*sqrt(I)*(11*a^3 + 6*a*b^2)*e^(7/2)*weierstrassPInverse(4, 0, cos(d*x + c) - I*sin(d*x + c)) +
2*(693*b^3*cos(d*x + c)^6*e^(7/2) + 2457*a*b^2*cos(d*x + c)^5*e^(7/2) + 77*(39*a^2*b - 14*b^3)*cos(d*x + c)^4
*e^(7/2) + 117*(11*a^3 - 36*a*b^2)*cos(d*x + c)^3*e^(7/2) - 77*(78*a^2*b - b^3)*cos(d*x + c)^2*e^(7/2) - 39*(8
8*a^3 - 15*a*b^2)*cos(d*x + c)*e^(7/2) + 77*(39*a^2*b + 4*b^3)*e^(7/2))*sqrt(sin(d*x + c)))/d

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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: SystemError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*cos(d*x+c))**3*(e*sin(d*x+c))**(7/2),x)

[Out]

Exception raised: SystemError >> excessive stack use: stack is 7316 deep

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*cos(d*x+c))^3*(e*sin(d*x+c))^(7/2),x, algorithm="giac")

[Out]

integrate((b*cos(d*x + c) + a)^3*e^(7/2)*sin(d*x + c)^(7/2), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\left (e\,\sin \left (c+d\,x\right )\right )}^{7/2}\,{\left (a+b\,\cos \left (c+d\,x\right )\right )}^3 \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*sin(c + d*x))^(7/2)*(a + b*cos(c + d*x))^3,x)

[Out]

int((e*sin(c + d*x))^(7/2)*(a + b*cos(c + d*x))^3, x)

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